Vit rich

This is the sort of thing i was looking at; http://cgi.ebay.co.uk/BUCHER-HYDRAULIC-1-BANK-LEVER-VALVE-100-L-MIN-3-4_W0QQitemZ310188714106QQcmdZViewItemQQptZLH_DefaultDomain_3?hash=item4838b0287a Mainly because the cheaper valves can only handel 45lpm, and the max flow of the motor im looking at is 60lpm. Sound reasonable? Oh and im only using Hydraulic on the front, im using a Goodwinch TDS on the back with a bow 2 motor and 24v turbo unit. You will need a pressure relief valve somewhere in the system. The lever operated valves used in mobile equipment can be supplied with a built in pressure relief valve. This will save space, hoses and fittings and make for a neater installation. Im assuming thats what the 'main relief valve' on the valve i am looking at above is? How do i know where to set this? At the max pressure of the system? I have read that whilst the main job of the relief valve is to stop the system bursting if a malfunction occures, it is also used to set the max pulling force of the winch, in that once the load becomes to hig, the pressure in the system becomes too large and the valve trips, but how is it possible to set this to be the case? By calculating the pressure of the system whilst the winch is at maximum pull? How would i go about doing this? You should use an overcentre valve - you only need one for each winch (because the load can only pull rope from the winch in one direction). Where abouts should this be located? Between the output of the directional controll valve and the motor? Consider the rated pressure for both the pump and motor. For the required rope pull, you can calculate the torque required at the winch drum, and then the torque required at the motor. Then for the pressure and torque select the motor size. Motor torque (Nm) = displacement (cm^3) x pressure (bar) / 62.8 or torque (lbf in) = disp (in^3) x pressure (psi) / 6.28 From required rope speed, determine drum speed then motor rotational speed (rpm). Then Flow rate (l/min) = disp (cm^3) x rpm / 1000 or flow (gal/min) = disp (in^3) x rpm / 192 The required pump size (displacement) can be chosen for the flow rate and pump speed. Ok, the motor im looking at is; http://cgi.ebay.co.uk/ws/eBayISAPI.dll?ViewItem&item=310177906347&ssPageName=STRK:MEWAX:IT Mated with either this pump; http://cgi.ebay.co.uk/ws/eBayISAPI.dll?ViewItem&item=320414356719&ssPageName=STRK:MEWAX:IT Or this one. http://cgi.ebay.co.uk/ws/eBayISAPI.dll?ViewItem&item=320414367456&ssPageName=STRK:MEWAX:IT Your formula confuse me slightly in that i carnt quite understand what i need to work out to make my selection. I know that pump 1 has a smaller displacement per stroke, but at a higher pressure, wereas pump 2 has a larger dispalcement, but at a lower pressure. I would say im looking for speed over power, its only to pull out a sub 1.5tonne suzuki based truck, so aslong as i can get 9 - 10,000lb pull from it in low gear im happy, anything other than than will be wasted. Thanks for all your help so far, as someone very wise once said, a little knowledge is a dangerous thing! Rich

Hi all, im new to this forum but many of you may know me from Difflock. Im looking at buying a milemaker hydraulic winch, and i have a few questions to go with this, iv had a search and whilst there are plenty of helpful topics they dont answer all my questions. Im looking at using an upgraded 100CC motor, of almost exact spec to the type R. What bolt pattern and shaft size should i be looking for or are they universal? For the pump, im looking at either a 78cc pump with a max cont pressure of 160 bar and a max pressure of 200 bar, or a 60cc pump but with a continuous pressure of 180 bar with a 230 bar max. The motor has a max continous pressure of 175 bar and a max intimittent of 200 bar. So would i be better off going with a larger pump displacement at a lower pressure or a small displacement with a higher pressure? What would be the advantages/disadvantages of going either way? I also hear that thhe solenoids of the milemakers are pretty crappy, so im looking at a lever control valve to replace it. What should i be looking for? A two way lever to control forwards and revese? So it would just change the flow direction depending on which position i put the lever in? The over center valve, am i correct in thisnking this acts like a brake on an electric winch? It will stop the car decending if i am holding it on the winch on a steep incline? Will this also allow me to go from stationary to lowering on a steep incline without having the intial drop as the system comes up to pressure again as it goes into revese? Can i get a lever controll valve with one of these valves built into it already? Will i need any other valves in there? Possibly an overload valve to stop the system over pressuring? If so what sort of pressure should i set this to as im guessing this will also stop me pulling to higher load with the winch by simply cutting it out? Does anyone have a diagram of how to set this whole system up? What about pipe bores? What sort of size should i be looking at using? Im guessing smaller but thicker walled from the pump to valve to the motor and back, then thiner but larger for the resevoir to the pump and back? I have pretty much decided to mount the pump direct via a UJ or similar to the crankshaft by moving the rad forwards slightly, this is being fitted to my project truck which has the body off atm so im trying to get everything fitted to the engine whilst it is nice and exposed. Thanks for your time and patients with me, im new to hydraulics so im just trying to get my head around it all. Thanks again and merry christmas Rich