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Maths model of a differential gearbox


LandyManLuke

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For an open diff, surely you just need:

Input speed = ratio * (output speed 1 + output speed 2)

Input torque = (output torque 1 + output torque 2) / ratio

BUT

output torque 1 = output torque 2

And alter equation 3 if you have a torque biasing diff. If the diff is locked, no 3 becomes (output speed 1 = output speed 2)

Or is that not what you meant? :huh:

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yuh, I've got those basics too, but

what about when a wheel lifts, there's no torque as there's no resistance. (neglecting drivetrain resistance)

what about marginal traction? speed, and torque, are a function of resistance.

I'm using an electric motor as a prime mover, so speed is a function of voltage and load torque, at that end of the drive train.

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Those equations cover it because they're simultaneous. Lift a wheel, output torque 2 = 0.

Output torque 1 = output torque 2, so output torque 1 = 0.

Input torque = (zero + zero) / ratio = 0

This is all capped by the input torque from your motor, which you can relate to the current draw?

(I still think you'll need a very refined model for inertia to up-scale it effectively)

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